++ 50 ++ factorise x(x^3-y^3) 3xy(x-y) 180063

FIRST, WE WILL DO THE DISPLACE MENT METHOID = 12XXY2Y= 12X3XY8In the given example of factorising the expression 3xy^2 6xy 1) We start by looking for common factors A common factor is a part of the expression that is included everywhere inside of the expression We can see that 3, x and y are all common factors 2) Now we have our common factors, we can move them to the front of our new expression andFactoriser Factoriser Enter a quadratic equation to factorise For indices use (^) Factorise Submit

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Factorise x(x^3-y^3) 3xy(x-y)

Factorise x(x^3-y^3) 3xy(x-y)-Solution x3 y3 =(x y) (x2 – xy y2) =(x y) (x y)2 – 3xy = 12 122 – 3 × 27 = 12 × 63 = 756 Alternative Solution x 3 y 3 =(x y)3 – 3xy (x y) = 123 – 3 × 27 × 12 = 12 122 – 3 × 27 = 12 × 63 = 756 EXERCISE 24 1 If the polynomials az3 4z2 3z – 4 and z3 – 4z a leave the same remainder when divided by z – 3, find the value of a 2 TheFactorise X2y2 3xy 40 CISCE ICSE Class 8 Textbook Solutions 7709 Important Solutions 5 Question Bank Solutions 69 Concept Notes & Videos 345

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Simplifying 6x 3 y 3xy 2 = 0 Reorder the terms 3xy 2 6x 3 y = 0 Solving 3xy 2 6x 3 y = 0 Solving for variable 'x' Factor out the Greatest Common Factor (GCF), '3xy' 3xy(1y 2x 2) = 0 Ignore the factor 3 Subproblem 1 Set the factor 'xy' equal to zero and attempt to solve Simplifying xy = 0 Solving xy = 0 Move all terms containing x to the left, all other terms to the rightFactorize x (x 3 y 3) 3xy ( x y ) Advertisement Remove all ads Solution Show Solution Elaborating x 3 y 3 using identity a 3 b 3 = (a b)(a 2 ab b 2) = x ( x y)(x 2 xy y 2) 3xy (x y ) Taking common x( x y ) in both the terms = x ( x y){x 2 xy y 2 3y} ∴ x (x 3 y 3) 3xy ( x y) = x ( x y )(x 2 xy y 2 3y) Concept Algebraic Expressions ReportAlgebra Factor (xy)^3 (xy)^3 (x y)3 − (x − y)3 ( x y) 3 ( x y) 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = xy a = x y and b = x− y b = x y

 Factorise x(x^3 y^3) 3xy(x y) system of equations step by step solver;Typo/misspeak around 4 minutes 369=27Multivariable Calculus Find all local maxima/minima and saddle points for the function f(x,y) = x^3 3xy y^3 WSmãrtyMohït SmãrtyMohït here is your answer New questions in Math please refer to image

(a) x 2 y 2 2xy (b) x 2 y 2 – xy (c) xy 2 (d) 3xy polynomialsFactor completely 27x3y4 9x2y2 3x3y3 a) 3x3y3(9y – 3) b) 9x2y2(3xy2– 1 xy) c) 3x2y2(9xy2– 3 xy) d) 3x2(9xy2 3y xy) 17 When completelyfactored, one of the binomial factors of 2x2 6x – 36 is a) x – 3 b) 2x 12 c) x 2 d) x 1 18 Factor completely 16x4– 9 a) (4x2– 3) (4x2– 3) b) (4x2– 3) (4x2 3) c) (16x2– 3 We need to differentiate x 3 y 3 ( x) = 3 x y ( x) Let's do each term one by one Differentiate x 3 You should quickly see this is 3 x 2 To differentiate ( y ( x)) 3, we need to remember the chain rule This can be written in many different ways, but this is a composition of the functions ( ⋅) 3 ∘ y ∘ x

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 Factorize x(x^3y^3) 3xy (xy) asked in Mathematics by Sonu khan (356k points) factorisation of algebraic expressions;The answer is D Now, (xy)^3 (x^3y^3) = (xy)^3 – (xy) (x^2 xyy^2) Using identity, a^3b^3 = (ab) (a^2 abb^2) =(xy)(xy)^2 – (x^2 – xy y^2) =(xy) Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange

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 Factor (Xy)^3=x^3y^33xy(xy) 1 See answer Advertisement Advertisement djw226 is waiting for your help Add your answer and earn points barfielddana0 barfielddana0 Answer x • (x y) • (x^2 xy y^2 3y) Stepbystep explanation Advertisement Advertisement New questions in Mathematics Create a set of 5 numbers that follows this rule 1,000 LESS Type View Full Answer Deep Sah, added an answer, on 3/10/15 Deep Sah answered this We know that a^3 b^3 c^3 3abc = (a b c) (a^2 b^2 c^2 ab bc ac) Take, a = xy, b = yz, c = zx we get, (xy)^3 (yz)^3 (zx)^3 3 (xy) (yz) (zx)27x^3y^3z^39xyz (3x)^3y^3z^39xyz we have a identity That is (a^3b^3c^3)=(abc)(a^2b^2c^2abbccb)3abc From the above identity here a=3x b=y c=z expand according to identity ,we get (3xyz)(9x^2y^2z^23xyyzyz33xyz) (3xyz)(9x^2y^2z^23xy3xz3xz)33xyz9xyz (3xyz)(9x^2y^2z^23xy3xzyz)

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Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam, (x^3y^3)=(xy)(x^2xyy^2) This is a sum of cubes This is a semiimportant identity to know (x^3y^3)=(xy)(x^2xyy^2) Although it doesn't apply directly to this question, it's also important to know that (x^3y^3)=(xy)(x^2xyy^2) This Find an answer to your question Factorize x(x3 – y3) 3xy(x – y) (c) 8 2736 बज 12 किमी0 लम्बे वर्ताकार मार्ग पर तीन धावक A, B, C एक ही समय पर, एक ही बिन्दु से तथा एक ही दिशा में क्रमशः 3 किमी0, 7 किमी0 व 13 कि

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Solve 3xy 2ay 2 Dx X 2 2axy Dy 0 Mathematics Stack Exchange

{eq}3x^3 x^2 y 6x^2 y 2xy^2 3xy^2 y^3 {/eq} Factoring Polynomial Expression A polynomial expression is composed of the sum of a constantAnswer (1 of 5) The way it is given to you, it is almost obvious that it is (3xy)x² (3xy)2xy (3xy)y² = (3xy)(x²2xyy²) = (3xy)(xy)² However, if you don't notice that and just sum like terms together, you get 3x³ 5x²y xy² y³ = x³(t³ t² 5t 3), where t=y/x Now the roots ofAnswer (1 of 5) At first glance (0,1) and (1,0) are solutions If it has a nice linear solution, fitting this then that would be y= x1, lets plug it in x^3 3x(x1) (x1)^3 1 = x^ 3x^2 3x 1 x^2 3x^2–3x1–1=0 Well, then lets try to factor out yx1 using the usual polynomial divis

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